-3
\(\frac{1}{9}\)
\(\frac{1}{3}\)
\(\frac{27}{8}\)
4
Correct answer is C
\(\frac{8^{\frac{2}{3}}*27^{\frac{-1}{3}}}{64^{\frac{1}{3}}}\) \(\frac{2^2*3^{-3}}{4} = 3^{-1} = \frac{1}{3}\)
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