Before starting a journey, the tyre pressure of a car was 3 x 105Nm-2 at 27oC. At the end of the journey, the pressure rose to 4 x 105Nm-2. Calculate the temperature of the tyre after the journey, assuming the volume is constant

A.

400oC

B.

300oC

C.

273oC

D.

127oC

Correct answer is D

\(\frac{P_1}{T_1}\) = \(\frac{ P_2}{T_2}\)

\(\frac{3 \times\ 10^6}{27 + 273}\) = \(\frac{4 \times\ 10^6}{0 + 273}\)

\(\theta\) = 127oC