If the radius of the earth is 6.4 x 106m, the escape...
If the radius of the earth is 6.4 x 106m, the escape velocity of a satellite from the earth is?
[g = 10 ms-2]
1.13 x 104 ms-1
9.00 x 103 ms-1
8.00 x 103 ms-1
1.27 x 104 ms-1
Correct answer is A
V = √2GM/R.
=√[2 x 6.67 x 10−11 x 6.0 x 1024] / 6.4 x 106
= √12.506 x 107
= 11,183.13
OR
V =√2gR
V=√[2 * 10 * 6.4 x 106]
V = √128,000,000
11,313.708