A block and tackle is used to raise a load of 250N through a vertical distance of 30m. What is the efficiency of the system if the work done against friction is 1500J?

A.

62.5%

B.

73.3%

C.

83.3%

D.

94.3%

View answer & explanation

Correct answer is C

Y = \(\frac{work output}{work input} \times \frac{100}{1}\)

Y = \(\frac{250 \times 30}{250 \times 30 + 1500} \times \frac{100}{1}\)

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