Calculate the energy of the third level of an atom if the ground state energy is - 24.8eV
-9.20eV
-8.20eV
-2.75eV
-1.75eV
Correct answer is C
\(E_3 = \frac{E}{n^2}\) \(E_3 = \frac{-24.8}{3^2}\) \(E_3 = 2.75eV\)
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