In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD

In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50^o. Find ∠ACD

A.

50^o

B.

60^o

C.

65^o

D.

100^o

E.

115^o

View answer & explanation

Correct answer is E

ACB = ABC [Base angles of isoceles triangle]
ACB + ABC + 50^o = 180^o[sum of angles in a triangle]
ACB + ABC = 180^o - 50^o = 130^o

ACB

130^o/2

= 65^o

ACD + ACB = 180^o[sum of ∠s on a straight line]
ACD + 65^o = 180^o
ACD = 180^o - 65^o = 115^o

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