A solid material of volume 100 $cm^{-3}$ is heated through a temperature difference of 40°C. Calculate the increase in the volume of the material if its linear expansitivity is 2 x $10^{-6}K{-1}$

2.4 x $10^{-2}cm^{-3}$

1.6 x $10^{-2}cm^{-3}$

8 x $10^{-2}cm^{-3}$

5 x $10^{-2}cm^{-3}$

4 x $10^{-2}cm^{-3}$

Correct answer is A

$3{\alpha}= \frac{\Delta{V}}{V_1\Delta{T}}\Rightarrow \frac{\Delta{V}}{100\times40}=3\alpha\, where\, \alpha = 2 \times 10^{-6}\\ \frac{\Delta{V}}{4000}=6\times10^{-6}\Rightarrow \Delta=4\times10^3\times6\times10^{-6}= 2.4\times10^{-2}cm^{-3}$

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A solid material of volume 100 $cm^{-3}$ is heated through a temperature difference of 40°C. Calculate the increase in the volume of the material if its linear expansitivity is 2 x $10^{-6}K{-1}$

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A solid material of volume 100 $cm^{-3}$ is heated through a temperature difference of 40°C. Calculate the increase in the volume of the material if its linear expansitivity is 2 x $10^{-6}K{-1}$