Physics Questions and Answers
If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
3.33%
5.55%
33.33%
55.55%
Correct answer is C
| RH | = | mass of water vapour in volume of air
mass of water vapour for saturation |
| RH | = | m
M |
= | 0.05
0.15 |
× | 100 | = | 5
0.15 |
= | 500
15 |
= | 33.33% |
A safety precaution designed to prolong the life of a lead acid accumulator is
By topping up the cells with concentrated acid
The use of naked flame when charging the battery
Keeping the specific gravity of the electrolyte within specified range
By connecting wires to the terminals directly when testing the level of charging
Correct answer is C
- Topping is done with distilled water
- Naked flame should be avoided when charging the battery
- Direct connection of wires to the terminals should be avoided.
4mm
0.25mm
2mm
0.12mm
Correct answer is B
l\(_1\) = 5m, ΔT = 10c, l\(_2\) - l\(_1\) = 1mm
l\(_1\) = 2.5m, ΔT = 5c, l\(_2\) - l\(_1\) = ?
| using | α | = | l\(_2\) - l\(_1\)
l\(_1\)ΔT |
| 1
5(10) |
= | l\(_2\) - l\(_1\)
2.5(5) |
| l\(_2\) | - | l\(_2\) | = | 2.5(5)
5(10) |
= | 1
4 |
= | 0.25mm |
Workdone on an object to bring it to a certain point in space is called
Gravitational potential energy
Potential energy
Kinetic energy
Mechanical energy
Correct answer is A
Gravitational potential energy is the energy an object possesses because of its position in a gravitational field. Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. (i.e, P.E\(_g\) = ωh, where ω = mg)
1.05 × 10\(^{-2}\)ms\(^{-1}\)
1.85 × 10\(^{-4}\)ms\(^{-1}\)
9.50 × 10\(^{-1}\)ms\(^{-1}\)
5.25 × 10\(^{-3}\)ms\(^{-1}\)
Correct answer is A
Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.
| Thus, | ω | = | θ | = | 2π
60 |
Velocity of the tip of the hand, V = ωr
| V | = | 2π
60 |
× | 0.1 | = | 2π
600 |
= | π
300 |
= | 3.142
300 |
V = 0.01047 = 1.05 × 10\(^{-2}\)ms\(^{-1}\)