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Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

446.

A safety precaution designed to prolong the life of a lead acid accumulator is

A.

By topping up the cells with concentrated acid

B.

The use of naked flame when charging the battery

C.

Keeping the specific gravity of the electrolyte within specified range

D.

By connecting wires to the terminals directly when testing the level of charging

Correct answer is C

- Topping is done with distilled water
- Naked flame should be avoided when charging the battery
- Direct connection of wires to the terminals should be avoided.

447.

A copper rod, 5m long when heated through 10c, expands by 1mm. If a second copper rod, 2.5m long is heated through 5c, by how much will it expand?

A.

4mm

B.

0.25mm

C.

2mm

D.

0.12mm

Correct answer is B

l1 = 5m, ΔT = 10c, l2 - l1 = 1mm
l1  = 2.5m, ΔT = 5c, l2 - l1 = ?

using α = l2 - l1
l1ΔT

 

1
5(10)
= l2 - l1
2.5(5)

 

l2 - l2 = 2.5(5)
5(10)
= 1
4
= 0.25mm

448.

Workdone on an object to bring it to a certain point in space is called

A.

Gravitational potential energy

B.

Potential energy

C.

Kinetic energy

D.

Mechanical energy

Correct answer is A

Gravitational potential energy is the energy an object possesses because of its position in a gravitational field. Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. (i.e, P.Eg = ωh, where ω = mg)

449.

The length of the seconds hand of laboratory clock is 0.1m. Calculate the speed at the top of the seconds hand

A.

1.05 × 102ms1

B.

1.85 × 104ms1

C.

9.50 × 101ms1

D.

5.25 × 103ms1

Correct answer is A

Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.

Thus, ω = θ =
60


Velocity of the tip of the hand, V = ωr

V =
60
× 0.1 =
600
= π
300
= 3.142
300


V = 0.01047 = 1.05 × 102ms1

450.

A projectile of mass 4kg is fired vertically and reaches a maximum height of 40m. Calculate the potential energy at the highest point
(g = 10ms2

A.

1800J

B.

1600J

C.

600J

D.

440J

Correct answer is B

Potential energy at the highest point = mgh
PE = 4 × 10 × 40 = 1600J