Physics Questions and Answers
If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
I, II and Ill
ll and ll only
l and lII only
I and II only
Correct answer is A
ripple tank experiment can be used to demonstrate the following properties of waves:
Reflection
Refraction
Diffraction
In which of the following media is the speed of sound the least?
Air
Brass
Water
Wood
Correct answer is A
No explanation has been provided for this answer.
A transverse pulse of frequency 9 Hz traves 4.5m in 0.6 s. Calculate the wavelength of the pulse.
3.33 m
0.30 m
0.83 m
1.20 m
Correct answer is C
Wavelength (\(\alpha\)) = \(\frac{Velocity (V)}{Frequency (f)}\)
Velocity = \(\frac{Distance}{Time}\) = \(\frac{4.5}{0.6}\)
= \(\frac{7.5}{9.0}\)
= 0.83m
78 °C
25 \(^o\)C
30\(^o\)C
57 \(^o\)C
Correct answer is D
Using the formula
t = \(\frac{R - R_0}{R_{(100)} - R_0} \times 100^oC\)
t = \(\frac{7.5 - 3.5}{10.5 - 2..5} \times 100^oC\)
= \(\frac{4}{7} \times 100\)
= 57.14\(^o\)C
~ 57\(^o\)C
4.80 kJ
20.16 kJ
40.32 kJ
22.17 kJ
Correct answer is C
Heat needed to change 60g (0.06kg) of ice at 0\(^o\)C to water at 0\(^o\)
= 0.06 x 3.36 x 10\(^5\)J
= 0.2016 x 10\(^5\) J
Heat required to raise the temp. of 60g (0.06kg) of water from 0\(^o\)C to 80\(^o\)C
= 0.06 x 4.2 x 10\(^3\) x (80.0)J
= 0.06 x 4.2 x 10\(^3\) x 80
= 20.16 x 10\(^3\)
= 0.2016 x 10\(^5\)
Total heat needed = (0.2016 + 0.2016) 10\(^5\)J
= 0.4032 x 10\(^5\) J
= 40.32KJ