Calculate the quantity of heat needed to change the tempe...
Calculate the quantity of heat needed to change the temperature of 60g of ice at 0 °C to 80 °C. [specific latent heat of fusion of ice= 3.36 x 105 Jkg−1 specific heat capacity of water 4.2 x 103 J kg−1 K−1]
4.80 kJ
20.16 kJ
40.32 kJ
22.17 kJ
Correct answer is C
Heat needed to change 60g (0.06kg) of ice at 0oC to water at 0o
= 0.06 x 3.36 x 105J
= 0.2016 x 105 J
Heat required to raise the temp. of 60g (0.06kg) of water from 0oC to 80oC
= 0.06 x 4.2 x 103 x (80.0)J
= 0.06 x 4.2 x 103 x 80
= 20.16 x 103
= 0.2016 x 105
Total heat needed = (0.2016 + 0.2016) 105J
= 0.4032 x 105 J
= 40.32KJ
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