Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

1,326.

The water manometer above is measuring the pressure of gas supply. if the specific gravity of mercury is 13.6 and the atmospheric pressure is 70cm of mercury what is the total pressure of the gas supply in cm of water

A.

67cm

B.

73cm

C.

949cm

D.

952cm

E.

955cm

Correct answer is E

Atmospheric pressure = 70cmHg (which is the height of mecury)
pressure = pgh = pwghw
Where
Pw = density of water
hw = height of water
ph = pwhw
13.6*70 = 1*hw
hw = 952cm

Pressure of gas in cm of water = 952 + 3 = 955cm

1,327.

Two taxis leave benin and agbor some 80km apart at 1200hr as shown above. from the distance time graph shown the distance of their meeting point P, from Benin and the time of their meeting are

A.

27km, 1218hr

B.

29km, 1315hr

C.

40km, 1418hr

D.

53km, 1436hr

E.

60km, 1500hr

Correct answer is B

No explanation has been provided for this answer.

1,328.

in a light experiment with a convex lens a student plotted a graph as shown above of the reciprocal of object distance (1)/u against the reciprocal of image distance (1)/v . the focal length of the lens is given as

A.

slope of line PQ

B.

Reciprocal of either OP or OQ

C.

Length OP or OQ

D.

area under the graph E ratio OP/OQ

Correct answer is B

The intercept on either of the axes of the graph of \(\frac{1}{u}\) against \(\frac{1}{v}\) gives the value of \(\frac{1}{f}\). Hence, the reciprocal of this intercecpt gives the value of the focal length. 

1,329.

The wave motion above has a frequency

A.

0.1Hz

B.

0.2Hz

C.

5Hz

D.

10Hz

E.

100Hz

Correct answer is C

No explanation has been provided for this answer.

1,330.

The effect of closing the key K in the circuit shown above would be to

A.

increase the current by 0.6A

B.

reduce the current by 0.6A

C.

increase the current by 0.4A

D.

keep the current unchanged

Correct answer is C

When K is open, the total resistance

R = 8\(\Omega\) + 2\(\Omega\) = 10\(\Omega\)

I = \(\frac{V}{R}\) = \(\frac{6}{10}\)

= 0.6A

When K is closed, we have

\(\frac{1}{R}\) = \(\frac{1}{8}\) + \(\frac{1}{8}\)

⇒ \(\frac{1}{R}\) = \(\frac{1}{4}\)

⇒ R = 4\(\Omega\)

The total resistance R = 4\(\Omega\) + 2\(\Omega\)

= 6\(\Omega\)

I = \(\frac{6}{6}\)

= 1A

Hence, I = 1A - 0.6A = 0.4A increase