How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Which of the following is not a sufficient condition for two triangles to be congruent?
AAS
SSS
SAS
SSA
Correct answer is D
No explanation has been provided for this answer.
120\(^o\)
90\(^o\)
75\(^o\)
60\(^o\)
Correct answer is B
m + n + 90\(^o\) + 180\(^o\) (sum of angle in a \(\triangle\))
m + n = 180\(^o\) - 90\(^o\)
m + n =90\(^o\)
x | 6.20 | 6.85 | 7.50 |
y | 3.90 | 5.20 | 6.50 |
The points on a linear graph are as shown in the table. Find the gradient (slope) of the line.
2\(\frac{1}{2}\)
2
1
\(\frac{1}{2}\)
Correct answer is B
Gradient = \(\frac{y_2 - y_ 1}{x_2 - x_1}\)
= \(\frac{5.20 - 3.90}{6.85 - 6.20}\)
= \(\frac{1.3}{0.5}\)
= 2
In the diagram, PQ is a straight line. If m = \(\frac{1}{2}\) (x + y + z), find value of m.
45\(^o\)
60\(^o\)
90\(^o\)
100\(^o\)
Correct answer is B
x + y + m + 2 = 180\(^o\)
\(\frac{x + y + 2}{2} + \frac{m}{2}\) = 90\(^o\)
m + \(\frac{m}{2} = 90^o\)
3m = 2 x 90\(^o\)
\(\frac{3m}{3} = \frac{180^o}{3}\)
m = 60\(^o\)
\(\frac{25}{144}\)
\(\frac{5}{33}\)
\(\frac{5}{6}\)
\(\frac{103}{132}\)
Correct answer is A
Pr(RR) = \(\frac{5}{12}\) = \(\frac{5}{12} \times \frac{5}{12} = \frac{25}{144}\)