How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the equation of a line perpendicular to line 2y = 5x + 4 which passes through (4, 2).
5y - 2x -18 = 0
5y + 2x - 18 = 0
5y - 2x + 18 = 0
5y + 2x - 2 = 0
Correct answer is B
2y = 5x + 4 (4, 2)
y = \(\frac{5x}{2}\) + 4 comparing with
y = mx + e
m = \(\frac{5}{2}\)
Since they are perpendicular
m1m2 = -1
m2 = \(\frac{-1}{m_1}\) = -1
\(\frac{5}{2}\) = -1 x \(\frac{2}{5}\)
The equator of the line is thus
y = mn + c (4, 2)
2 = -\(\frac{2}{5}\)(4) + c
\(\frac{2}{1}\) + \(\frac{8}{5}\) = c
c = \(\frac{18}{5}\)
y = -\(\frac{2}{5}\)x + \(\frac{18}{5}\)
5y = -2x + 18
or 5y + 2x - 18 = 0
The midpoint of P(x, y) and Q(8, 6) is (5, 8). Find x and y.
(2, 10)
(2, 8)
(2, 12)
(2, 6)
Correct answer is A
P(x, y) Q(8, 6)
midpoint = (5, 8)
x + 8 = 5
\(\frac{y + 6}{2}\) = 8
x + 8 = 10
x = 10 - 8 = 2
y + 6 = 16
y + 16 - 6 = 10
therefore, P(2, 10)
The perpendicular bisector of a line XY is the locus of a point
whose distance from X is always twice its distance from Y
whose distance from Y is always twice its distance from X.
which moves on the line XY
which is equidistant from the points X and Y
Correct answer is D
No explanation has been provided for this answer.
48 cm3
33 cm3
60 cm3
27 cm3
Correct answer is B
Volume of cube = L3
33 = 27cm3
volume of rectangular tank = L x B X h
= 3 x 4 x 5
= 60cm3
volume of H2O the tank can now hold
= volume of rectangular tank - volume of cube
= 60 - 27
= 33cm3
4√6 cm
3√6 cm
6√6 cm
2√6 cm
Correct answer is A
From Pythagoras theorem
|OA|2 = |AN|2 + |ON|2
72 = |AN|2 + (5)2
49 = |AN|2 + 25
|AN|2 = 49 - 25 = 24
|AN| = \(\sqrt {24}\)
= \(\sqrt {4 \times 6}\)
= 2√6 cm
|AN| = |NB| (A line drawn from the centre of a circle to a chord, divides the chord into two equal parts)
|AN| + |NB| = |AB|
2√6 + 2√6 = |AB|
|AB| = 4√6 cm