Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,436.

Evaluate \(\frac{0.36 \times 5.4 \times 0.63}{4.2 \times 9.0 \times 2.4}\)

A.

0.013

B.

0.014

C.

0.14

D.

0.13

Correct answer is B

\(\frac{0.36 \times 5.4 \times 0.63}{4.2 \times 9.0 \times 2.4}\)

= \(\frac{36}{420} \times \frac{54}{90} \times \frac{63}{240}\)

= \(\frac{6}{70} \times \frac{18}{30} \times \frac{21}{80}\)

= \(\frac{27}{2000}\)

= 0.0135

\(\approx\) = 0.014

2,437.

Evaluate \(\frac{1}{3} \div [\frac{5}{7}(\frac{9}{10} -1 + \frac{3}{4})]\)

A.

\(\frac{28}{39}\)

B.

\(\frac{13}{39}\)

C.

\(\frac{39}{28}\)

D.

\(\frac{84}{13}\)

Correct answer is A

\(\frac{1}{3} \div [\frac{5}{7}(\frac{9}{10} -1 + \frac{3}{4})]\)

\(\frac{1}{3} \div [\frac{5}{7}(\frac{9}{10} - \frac{10}{10} + \frac{3}{4})]\)

= \(\frac{1}{3} \div [\frac{5}{7}(\frac{-1}{10} + \frac{3}{4})]\)

= \(\frac{1}{3} \div [\frac{5}{7}(\frac{-2 + 15}{20})]\)

= \(\frac{1}{3} \div [\frac{5}{7} \times \frac{13}{20}]\)

\(\frac{1}{3} + [\frac{13}{28}]\) = \(\frac{1}{3} \times \frac{28}{13}\)

= \(\frac{28}{39}\)

2,438.

The mean of twelve positive numbers is 3. When another number is added, the mean becomes 5. Find the thirteenth number

A.

29

B.

26

C.

25

D.

24

Correct answer is A

Let the sum of the 12 numbers be x and the 13th number be y.

\(\frac{x}{12} = 3 \implies x = 36\)

\(\frac{36 + y}{13} = 5 \implies 36 + y = 65\)

\(y = 65 - 36 = 29\)

2,439.

Solve for x if \(25^{x} + 3(5^{x}) = 4\)

A.

1 or -4

B.

0

C.

1

D.

-4 or 0

Correct answer is B

\(25^{x} + 3(5^{x}) = 4\)

Let \(5^{x}\) = y.

\((5^{2})^{x} + 3(5^{x}) - 4 = 0\)

\(y^{2} + 3y - 4 = 0\)

\(y^{2} - y + 4y - 4 = 0\)

\(y(y - 1) + 4(y - 1) = 0\)

\((y + 4)(y - 1) = 0\)

\(y = -4 ; y = 1\)

y = -4 is not possible.

y = 1 \(\implies\) x = 0.

2,440.

A die has four of it's faces coloured white and the remaining two coloured black. What is the probability that when the die is thrown two consecutive time, the top face will be white in both cases?

A.

\(\frac{5}{3}\)

B.

\(\frac{1}{9}\)

C.

\(\frac{4}{9}\)

D.

\(\frac{1}{36}\)

Correct answer is C

\(\begin{array}{c|c} & W & W & W & W & B & B \\ \hline W & WW & WW & WW & WW & WB & WB \\ W & WW & WW & WW & WW & WB & WB\\W & WW & WW & WW & WW & WB & WB\\ W & WW & WW & WW & WW & WB & WB\\ B & BW & BW & BW & BW & BB & BB \\ B & BW & BW & BW & BW & BB & BB\end{array}\)

P(WW) = \(\frac{16}{36}\)

= \(\frac{4}{9}\)