How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
| Height(cm) | 160 | 161 | 162 | 163 | 164 |
165 |
| No. of players | 4 | 6 | 3 | 7 | 8 | 9 |
the table shows the height of 37 players of a basketball team calculates correct to one decimal place the mean height of the players.
163.0
162.0
160.0
165.0
Correct answer is A
∑fx = (160 * 4) + (161 * 6) + (162 * 3) + (163 * 7) + (164 * 8) + (165 * 9)
=640 + 966 + 486 + 1,141 + 1,312 + 1,485
= 6,030
∑f = 4 + 6 + 3 + 7 + 8 + 9
= 37
= \(\frac{∑fx}{∑f}\)
= \(\frac{6030}{37}\)
= 162.97 or 163
112
90
68
22
Correct answer is C
No explanation has been provided for this answer.
Given that sin x = 3/5, 0 ≤ x ≤ 90, evaluate (tanx + 2cosx)
2\(\frac{11}{20}\)
\(\frac{11}{20}\)
2\(\frac{7}{20}\)
\(\frac{1}{20}\)
Correct answer is B
Sin x = \(\frac{opp}{hyp}\)
sinx = \(\frac{3}{5}\)
using Pythagoras' theorem
hyp\(^2\) = opp\(^2\) + adj\(^2\)
adj\(^2\) = 5\(^2\) - 3\(^2\) = 25 - 9
adj\(^2\) = 16
adj = √ 16
adj = 4.
tanx = \(\frac{opp}{adj}\)
= \(\frac{3}{4}\)
cosx = \(\frac{adj}{hyp}\)
= \(\frac{4}{5}\)
(tanx + 2cosx) = \(\frac{3}{4}\) + 2(\(\frac{4}{5}\))
= \(\frac{15 + 32}{20}\)
= \(\frac{47}{20}\) or
2 \(\frac{7}{20}\)
341.98cm\(^2\)
276.57cm\(^2\)
201.14cm\(^2\)
477.71cm\(^2\)
Correct answer is A
Where l\(^2\) = h\(^2\) + r\(^2\)
l\(^2\) = 11\(^2\) + 8\(^2\)
l = √185
l = 13.60cm
The formula of CSA of Cone is πrl
\(\frac{22}{7}\) * 8 * 13.60
= 341.979 or 341.98 (2d.p)
In the diagram, PQRS is a circle. find the value of x.
50°
30°
80°
100°
Correct answer is A
Opp. angles in a cyclic quadrilateral always add up to 180°
∠P + ∠R & ∠Q + ∠S = 180
x + x+y = 180
2x + y = 180... i
2y - 30 + x = 180
2y + x = 180 + 30
x + 2y = 210 ... ii
Elimination method:
(2x + y = 180) * 1 --> 2x + y = 180
(x + 2y = 210) * 2 --> 2x + 4y = 420
Subtracting both equations
- 3y = - 240
y = 80°
using eqn i
2x + y = 180
2x + 80 = 180
2x = 100
x = 50°