How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
3
16
18
32
Correct answer is D
Mean of 10 numbers = 16
The total sum of numbers = 16 x 10 = 160
Mean of 11 numbers = 18
Total sum of numbers = 11 x 18
= 198
The 11th no. = 198 - 160
= 38
3
16
18
32
Correct answer is D
Mean of 10 numbers = 16
The total sum of numbers = 16 x 10 = 160
Mean of 11 numbers = 18
Total sum of numbers = 11 x 18
= 198
The 11th no. = 198 - 160
= 38
48o
84o
92o
276o
Correct answer is D
Given that 4, 16, 30, 20, 10, 14 and 26
Adding up = 120
nos \(\geq\) 16 are 16 + 30 + 20 + 26 = 92
The requires sum of angles = \(\frac{92}{120}\) x \(\frac{360^o}{1}\)
= 276o
perpendicular bisector of the two lines
angle bisector of the two lines
bisector of the two lines
line parallel to the two lines
Correct answer is B
The required locus is angle bisector of the two lines
If the heights of two circular cylinder are in the ratio 2 : 3 and their volumes?
27 : 32
27 : 23
23 : 32
27 : 23
Correct answer is A
\(\frac{h_1}{h_2}\) = \(\frac{2}{3}\)
h2 = \(\frac{2h_1}{3}\)
\(\frac{r_1}{r_2}\) = \(\frac{9}{8}\)
r2 = \(\frac{9r_1}{8}\)
v1 = \(\pi\)(\(\frac{9r_1}{8}\))2(\(\frac{2h_1}{3}\))
= \(\pi\)r1 2h1 x \(\frac{27}{32}\)
v = \(\frac{\pi r_1 2h_1 \times \frac{27}{32}}{\pi r_1 2h_1}\) = \(\frac{27}{32}\)
v2 : v1 = 27 : 32