How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
18
15
10
5
Correct answer is D
No of students offering Physics are \(\frac{12}{360}\) x 150
= 5
Find correct to one decimal place, 0.24633 \(\div\) 0.0306
0.8
1.8
8.0
8.1
Correct answer is D
\(\frac{0.24633}{0.03060}\) multiplying throughout by 100,000
= \(\frac{24633}{3060}\)
= 8.05
= 8.1
182
91
63
28
Correct answer is B
\(T_{n} = ar^{n - 1}\) (nth term of a G.P)
\(T_{4} = ar^{3} = 189\)
\(7 \times r^{3} = 189 \implies r^{3} = 27\)
\(r = \sqrt[3]{27} = 3\)
\(S_{n} = \frac{a(r^{n} - 1)}{r - 1}\)
\(S_{3} = \frac{7(3^{3} - 1)}{3 - 1} \)
= \(\frac{7 \times 26}{2} = 91\)
4
8
6\(\frac{2}{3}\)
9\(\frac{1}{3}\)
Correct answer is D
Let the first term and common difference = a & d respectively.
\(T_{n} = \text{nth term} = a + (n - 1) d\) (A.P)
Given: \(T_{4} = -6 \implies a + 3d = -6 ... (i)\)
\(T_{8} + T_{9} = 72\)
\(\implies a + 7d + a + 8d = 72 \implies 2a + 15d = 72 ... (ii)\)
From (i), \(a = -6 - 3d\)
\(\therefore\) (ii) becomes \(2(-6 - 3d) + 15d = 72\)
\(-12 - 6d + 15d = 72 \implies 9d = 72 + 12 = 84\)
\(d = \frac{84}{9} = 9\frac{1}{3}\)
y = 1 - x
y = 1 + x
y = x - 1
y = 3x + 3
Correct answer is A
The second graph is
\((x^{2} - 2x - 1) + (2 + x - x^{2})\)
= \(1 - x\)