How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
18
17\(\frac{1}{2}\)
16
15
Correct answer is D
Re-arranging them 2, 3, 5, 7, 8, 9, 12, 14
Mean = P and median = Q
P = \(\frac{2 + 2 + 5 + 7 + 8 + 9 + 12 + 14}{8}\)
\(\frac{60}{8}\) = 7.5
median (Q) = \(\frac{7 + 8}{2}\)
\(\frac{15}{2}\) = 7.5
P + Q = 7.5 + 7.5 = 15
21
40
91
96
Correct answer is C
Let x rep. number of goals
\(\begin{array}{c|c} "f & " & frequency\\\hline x & f & fx\\ 0 & 4 & 0\\1 & 3 & 3\\2 & 15 & 30\\3 & 16 & 48\\4 & 1 & 4\\5 & 0 & 0 \\ 6 & 1 & 6\end{array}\)
\(\sum fx\) = 91
Total number of goals scored is \(\sum fx\)= 91
187o30'
172o30'
135o225o
202o30' 157o 30'
Correct answer is D
Period of day light is from 5.30 to 7.00p.m - 13hrs 30min. interval
24hrs make 1 day
∴ period of darkness = 24hrs - 13hrs 30mins = 10hrs 30mins.
Angle of sector of daylight = \(\frac{13 \times 60 + 30 \times 360}{(24 \times 60)}\)
= \(\frac{810}{1440}\) x 360o
= \(\frac{291600}{1440}\)
= 202.5o
202.5o = 202.30o
darkness period = 360o - 202o 30'
= 157o30'
= 202o30' 157o 30'
A circle of radius 4 cm and with centre O
The perpendicular bisector of the chords
A straight line passing through centre O
A circle of radius 6 cm and with centre O
Correct answer is A
The locus of the mid-point of all chords of length 6cm within a circle of radius 5cm and with centre O is the perpendicular bisectors of the chords.
6cm
5cm
4cm
3cm
Correct answer is C
Base of pyramid of a square of side 8cm vertex directly above the centre edge = \(4\sqrt{3}\)cm
From the diagram, the diagonal of one base is AC2 = 82 + 82
Ac2 = 64 + 64 = 128
AC = \(8\sqrt{2}\)
but OC = \(\frac{1}{2}\)AC = 8\(\sqrt{\frac{2}{2}}\) = \(4\sqrt{2}\)cm
OE = h = height
h2 = (\(4\sqrt{3}\))2
16 x 2 - 16 x 2
48 - 32 = 16
h = \(\sqrt{16}\)
= 4