Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,036.

\(\frac{0.0001432}{1940000}\) = k x 10n where 1 \(\leq\) k < 10 and n is a whole number. The values K and n are

A.

7.381 qnd -11

B.

2.34 and 10

C.

3.871 and 2

D.

7.831 and -11

Correct answer is A

\(\frac{0.0001432}{1940000}\) = k x 10n

where 1 \(\leq\) k \(\leq\) 10 and n is a whole number. Using four figure tables, the eqn. gives 7.38 x 10-11

k = 7.381, n = -11

2,037.

Simplify \(\frac{(\frac{2}{3} - \frac{1}{5}) - \frac{1}{3} \text{of} \frac{2}{5}}{3 - \frac{1}{1 \frac{1}{2}}}\)

A.

\(\frac{1}{7}\)

B.

7

C.

\(\frac{1}{3}\)

D.

3

Correct answer is A

\(\frac{2}{3} - \frac{1}{5}\) = \(\frac{10 - 3}{15}\)

= \(\frac{7}{15}\)

\(\frac{1}{3}\) Of \(\frac{2}{5}\) = \(\frac{1}{3}\) x \(\frac{2}{5}\)

= \(\frac{2}{15}\)

(\(\frac{2}{3} - \frac{1}{5}\)) - \(\frac{1}{3}\) of \(\frac{2}{5}\)

= \(\frac{7}{15} - \frac{2}{15}\) = \(\frac{1}{3}\)

3 - \(\frac{1}{1 \frac{1}{2}}\) = 3 - \(\frac{2}{3}\)

= \(\frac{7}{3}\)

\(\frac{\frac{2}{3} - \frac{1}{5} \text{of} \frac{2}{15}}{3 - \frac{1}{1 \frac{1}{2}}}\)

= \(\frac{\frac{1}{3}}{\frac{7}{3}}\)

= \(\frac{1}{3}\) x \(\frac{3}{7}\)

= \(\frac{1}{7}\)

2,038.

If a{\(\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}\)} = 6x. Find a in its simplest form

A.

x2 - 1

B.

x2 + 1

C.

x2 + 4

D.

x2 - 4

E.

1

Correct answer is D

a{\(\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}\)} = a{\(\frac{(x + 1)(x + 2)- (x - 1)(x - 2)}{(x - 2)(x + 2)}\)}

= 6

\(\frac{6x}{x^2 - 4}\) = 6x

a = x2 - 4

2,040.

Two points X and Y both on latitude 60oS have longitude147oE and 153oW respectively. Find to the nearest kilometer the distance between X and Y measured along the parallel of latitude(Take 2\(\pi\)R = 4 x 104km, where R is the radius of the earth)

A.

16667km

B.

28850km

C.

8333km

D.

2233km

Correct answer is A

Length of an area = \(\frac{\theta}{360}\) x 2\(\pi\)r

Longitude difference = 147 + 153 = 30NoN

distance between xy = \(\frac{\theta}{360}\) x 2\(\pi\)R cos60o

= \(\frac{300}{360}\) x 4 x 104 x \(\frac{1}{2}\)

= 1.667 x 104km(1667 km)