How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
15o, 25o, 35o, 40o, 65o
60o, 100o, 140o, 160o, 260o
6o, 10o, 14o, 16o, 26o
30o, 50o, 70o, 80o, 130o
none of the above
Correct answer is D
6 + 10 + 14 + 16 + 26 = 72
\(\frac{6}{72}\) x 360
= 30o
Similarly others give 30o, 50o, 70o, 80o and 130o respectively
-3
3
-9
13
9
Correct answer is A
When x = -2, y = x3 - x + 3
= -23 - (-2) + 3
= -8 + 2 + 3
= -3
Solve the simultaneous equations for x in x2 + y - 8 = 0, y + 5x - 2 = 0
-28, 7
6, -28
6, -1
-1, 7
3, 2
Correct answer is C
x2 + y - 8 = 0, y + 5x - 2 = 0
Rearranging, x2 + y = 8.....(i)
5x + y = 2.......(ii)
Subtract eqn(ii) from eqn(i)
x2 - 5x - 6 = 0
(x - 6)(x + 1) = 0
x = 6, -1
u = \(\frac{8}{v^3}\)
v = \(\frac{8}{u^2v^3}\)
u = 8v3
v = 8u2
Correct answer is A
W \(\alpha\) \(\frac{1}{v}\)u \(\alpha\) w3
w = \(\frac{k1}{v}\)
u = k2w3
u = k2(\(\frac{k1}{v}\))3
= \(\frac{k_2k_1^2}{v^3}\)
k = k2k1k2
u = \(\frac{k}{v^3}\)
k = uv3
= (1)(2)3
= 8
u = \(\frac{8}{v^3}\)
Simplify log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7
1
\(\frac{7}{6}\)log10 a
zero
10
Correct answer is C
log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7 = log10 a\(\frac{1}{3}\) + log10\(\frac{1}{4}\) - log10 a\(\frac{7}{12}\)
= log10 a\(\frac{7}{12}\) - log10 a\(\frac{7}{12}\)
= log10 1 = 0