How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The equivalent of (10110.011)\(_2\) in base 10 is?
26.325
24.372
42.443
22.375
Correct answer is D
Using the expansion method on (10110.011)\(_2\)
(1 * 2\(^4\)) + (0 * 2\(^3\)) + (1 * 2\(^2\)) + (1 * 2\(^1\)) (0 * 2\(^0\)) + (0 * 2\(^{-1}\)) + (1 * 2\(^{-2}\)) + (1 * 2\(^{-3}\))
(1*16) + 0 (1*4) + (1*2) + 0 + 0 + (1*\(\frac{1}{4}\)) + (1*\(\frac{1}{8}\))
16 + 4 + 2 + (0.25 + 0.125)
22 + 0.375
(10110.011)\(_2\) = 22.375\(_{10}\)
Calculate the median of 14, 17, 10, 13, 18 and 10.
12.5
13.5
13.2
14.5
Correct answer is B
When rearranged: 10, 10, 13, 14, 17, 18
median = \(\frac{13+14}{2}\)
= \(\frac{27}{2}\) or 13.5
Find the equation of a straight line parallel to the line 2x - y = 5 and having intercept of 5
2x + y = 5
2x + y = -5
2x - y = -5
2x - y = 5
Correct answer is C
Condition for Parallelism means that their gradient value is same
line 2x - y = 5 is rearranged
As y = 2x - 5 from y = mx + c
: line 2x - y = 5 has the gradient of 2
A parallel line with gradient of 2 and intercept of 5
→ 2x - y = -5
Rearranged as y = 2x + 5
Find the limit of y = \(\frac{x^3 + 6x - 7}{x-1}\) as x tends to 1
9
8
0
7
Correct answer is A
\(\frac{x^3 + 6x - 7}{x-1}\):
When numerator is differentiated → 3x\(^2\) + 6
When denominator is differentiated → 1
: \(\frac{3x^2 + 6}{1}\)
substitute x for 1
\(\frac{3 * 1^2 + 6}{1}\) = \(\frac{3 + 6}{1}\)
= \(\frac{9}{1}\)
= 9
If sec\(^2\)θ + tan\(^2\)θ = 3, then the angle θ is equal to?
90º
30º
45º
60º
Correct answer is C
Given that sec\(^2\)θ + tan\(^2\)θ = 3
Where sec\(^2\)θ = 1 + tan\(^2\)θ
: 1 + tan\(^2\)θ + tan\(^2\)θ = 3
2tan\(^2\)θ = 3 - 1
2tan\(^2\)θ = 2
divide both sides by 2
tan\(^2\)θ = 1
tanθ = √1
tanθ = 1
θ = tan\(^{-1}\) (1)
θ = 45º