How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
0.00012m
0.0000012m
0.000012m
0.00000012m
0.000000012m
Correct answer is C
1 UM = 10-6mm = 10-9m
1.2 x 104 x 10-9m = 1.2 x 10-5m (0.000012)
7cm
12cm
8cm
36cm
69cm
Correct answer is A
In \(\Delta DAC, \stackrel\frown{DAC} = \theta\)
\(\sin \theta = \frac{5}{13}\)
\(\theta = 22.6°\)
\(< DOC = 22.6° \times 2 = 45.2°\)
\(\sin 45.2 = \frac{5}{r} \implies r = \frac{5}{\sin 45.2}\)
\(r = 7.046cm\)
= \(7\frac{1}{24} cm\)
N180.00
N59.00
N63.00
N58.00
N55.00
Correct answer is E
When C.P = N45.00 at 8% profit
C.P = \(\frac{100}{108}\) x 45
at profit of 32%, S.P = \(\frac{132}{100}\) x c.p
= \(\frac{132}{100}\) x \(\frac{100 \times 45}{108}\)
= \(\frac{5940}{108}\)
= N55.00
7\(\frac{1}{2}\) years
10 years
5 years
12 years
14 years
Correct answer is B
\(A = P(1 + \frac{R}{100})^{T}\)
\(285.20 = P(1 + \frac{5}{100})^{3}\)
\(285.20 = P(1.05)^{3} \implies 1.16P = 285.20\)
\(P = \frac{285.20}{1.16} = $245.86\)
Given Amount = $434.00
Interest = Amount - Principal
Interest = $434.00 - $245.86 = $188.14
\(T = \frac{100I}{PR}\)
\(T = \frac{100 \times 188.14}{245.86 \times 7.5}\)
\(T = \frac{18814}{1843.95} = 10.2\)
Approximately 10 years.
13years
12 years 7\(\frac{1}{2}\) months
13 years 5 months
13 years 10 months
11 years
Correct answer is D
Total age of the 7 pupils = 7 x 12 = 84
Total age of the 25 pupils = 25 x 14 = 350
Total age of the 6 pupils = 6 x 11 = 66
7 pupils leaving a class of 25 pupils given 18 pupils
Total age of the 18 pupils = 350 - 84 = 266
6 pupils joining 18 pupils = 24
Total age of 24 pupils = 266 + 66 = 332
Average age of 24 pupils now in class \(\frac{332}{24}\)
= 13yrs 10 months