Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

586.

Solve: - \(\frac{1}{4}\) < \(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\)

A.

-\(\frac{5}{9}\) < x <\(\frac{8}{9}\)

B.

-\(\frac{8}{9}\) < x <\(\frac{7}{9}\)

C.

-\(\frac{8}{9}\) < x <\(\frac{5}{9}\)

D.

-\(\frac{7}{9}\) < x <\(\frac{8}{9}\)

Correct answer is A

\(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\); \(\frac{3}{4}\) (3x - 2) > - \(\frac{1}{4}\)

3(3x - 2) < 2; 3(3x - 2) > -1

9x - 6 < 2; 9x - 6 > -1

9x < 8; 9x > 5

x < \(\frac{5}{9}\); x > \(\frac{8}{9}\)

587.

One factor of \(7x^2 + 33x - 10\) is

A.

7x + 5

B.

x - 2

C.

7x - 2

D.

x - 5

Correct answer is C

\(7x^2 + 33x - 10\)

\(7x^2 + 35x - 2x - 10\)

7x (x + 5) - 2 (x + 5)

(7x - 2) (x + 5)

588.

A sum of N18,100 was shared among 5 boys and 4 girls with each boy taking N20.00 more than each girl. Find a boy's share.

A.

N1,820.00

B.

2,000.00

C.

N2,020.00

D.

N2,040.00

Correct answer is C

Let a girl's share = x + 20

4x + 5(x + 20) = 18,100

4x + 5x + 100 = 18,100

9x + 100 = 18,100

9x = 18,000

x = \(\frac{18,000}{9}\)

x = 2,000

\(\therefore\) Each boy gets N(2,000 + 20)

 = N2,020.

589.

Solve the equation: \(\frac{1}{5x} + \frac{1}{x}\)= 3

A.

\(\frac{1}{5}\)

B.

\(\frac{2}{5}\)

C.

\(\frac{3}{5}\)

D.

\(\frac{4}{5}\)

Correct answer is B

\(\frac{1}{5x} + \frac{1}{x}\)= 3

\(\frac{1 + 5}{5x}\) = 3

6 = 15x

x = \(\frac{6}{15}\)

= \(\frac{2}{5}\)

590.

If x = \(\frac{2}{3}\) and y = - 6, evaluate xy - \(\frac{y}{x}\)

A.

0

B.

5

C.

8

D.

9

Correct answer is B

x = \(\frac{2}{3}\) and y = - 6

xy - \(\frac{y}{x}\)

\(\frac{2}{3} - (6)^2 - (-6) \div \frac{2}{3}\)

= -4 - (6) x \(\frac{3}{2}\)

= -4 - (-6) x \(\frac{3}{2}\)

= -4 - (-9)

= -4 + 9

= 5