How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The marks scored by 30 students in a Mathematics test are recorded in the table below:
| Scores (Mark) | 0 | 1 | 2 | 3 | 4 | 5 |
| No of students | 4 | 3 | 7 | 8 | 6 | 2 |
What is the total number of marks scored by the children?
82
15
63
75
Correct answer is D
| Scores (Mark) | 0 | 1 | 2 | 3 | 4 | 5 | |
| No of students | 4 | 3 | 7 | 8 | 6 | 2 | |
| fx | 0 | 3 | 14 | 24 | 24 | 10 | 75 |
56 cm\(^2\)
24 cm\(^2\)
42 cm\(^2\)
34 cm\(^2\)
Correct answer is D
Area of rectangle ABCD = length x breadth
= 7 x 4
= 28 cm\(^2\)
Area of triangle CDE = \(\frac{1}{2}\) base x height
= \(\frac{1}{2} \times 3 \times 4\)
= 6 cm\(^2\)
Area of the figure = 28 cm\(^2\) + 6 cm\(^2\)
= 34 cm\(^2\)
If \(4\sin^2 x - 3 = 0\), find the value of x, when 0° \(\leq\) x \(\leq\) 90°
90°
45°
60°
30°
Correct answer is C
\(4\sin^2 x - 3 = 0\)
\(4 \sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}\)
\(\sin x = \frac{\sqrt{3}}{2}\)
\(\therefore x = \sin^{-1} (\frac{\sqrt{3}}{2})\)
x = 60°
From the cyclic quadrilateral MNOP above, find the value of x.
16°
25°
42°
39°
Correct answer is D
The sum of two opposite angles of a cyclic quadrilateral = 180°
\(\therefore\) (2x + 18)° + 84° = 180°
2x + 102° = 180° \(\implies\) 2x = 78°
x = 39°
bisector of the two lines
line parallel to the two lines
angle bisector of the two lines
perpendicular bisector of the two lines
Correct answer is C
The locus of a points equidistant from two intersecting straight lines is a pair of bisectors that bisect the angles formed by the two intersecting lines.