Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

491.

Find the value of \(\frac{(0.5436)^3}{0.017 \times 0.219}\) to 3 significant figures.

A.

46.2

B.

43.1

C.

534

D.

431

Correct answer is B

(\frac{(0.5436)^3}{0.017 \times 0.219}\)

= \(\frac{0.16063}{0.017 \times 0.219}\)

= 43.1 (to 3 s.f)

492.

Simplify 81\(^{\frac{-3}{4}}\) x 25\(^{\frac{1}{2}}\) x 243\(^{\frac{2}{5}}\)

A.

\(\frac{2}{5}\)

B.

\(\frac{3}{5}\)

C.

\(\frac{5}{2}\)

D.

\(\frac{5}{3}\)

Correct answer is D

81\(^{\frac{-3}{4}}\) x 25\(^{\frac{1}{2}}\) x 243\(^{\frac{2}{5}}\)

= \((\sqrt[4]{81})^{-3} \times \sqrt{25} \times (\sqrt[5]{243})^2\)

= \(\frac{5 \times 3^2}{3^{3}}\)

= \(\frac{5}{3}\)

493.

The simple interest on ₦8550 for 3 years at x% per annum is ₦4890. Calculate the value of x to the nearest whole number.

A.

19%

B.

20%

C.

25%

D.

16.3%

Correct answer is A

S.I = \(\frac{PRT}{100}\)

\(\implies\) N 4890 = \(\frac{8550 \times 3 \times x}{100}\)

\(x = \frac{4890 \times 100}{8550 \times 3}\)

\(x = 19.06%\)

\(x \approxeq 19%\)

494.

Tade bought 200 mangoes at 4 for ₦2.50. 30 out of the mangoes got spoilt and the remaining were sold at 2 for ₦2.40. Find the percentage profit or loss.

A.

43.6% loss

B.

35% profit

C.

63.2% profit

D.

28% loss

Correct answer is C

200 mangoes at 4 for N2.50

\(\implies\) Total cost price = \(\frac{200}{4} \times N 2.50\)

= N 125.00

Since 30 mangoes got spoilt \(\implies\) Left over = 200 - 30

= 170 mangoes 

170 mangoes at 2 for N 2.40

\(\implies\) Total selling point = \(\frac{170}{2} \times N 2.40\)

= N 204.00

Profit : N (204.00 - 125.00) = N 79.00

% profit = \(\frac{79}{125} \times 100%\)

= 63.2% profit.

495.

If P varies inversely as the square root of q, where p = 3 and q = 16, find the value of q when p = 4.

A.

12

B.

8

C.

9

D.

16

Correct answer is C

\(p \propto \frac{1}{\sqrt{q}}\)

\(\implies p = \frac{k}{\sqrt{q}}\)

when p = 3, q = 16.

\(3 = \frac{k}{\sqrt{16}}\)

\(k = 3 \times 4 = 12\)

\(\therefore p = \frac{12}{\sqrt{q}}\)

when p = 4,

\(4 = \frac{12}{\sqrt{q}} \implies \sqrt{q} = \frac{12}{4}\)

\(\sqrt{q} = 3 \implies q = 3^2 \)

\(q = 9\)