Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

466.

Find the probability that a number selected at random from 21 to 34 is a multiple of 3

A.

\(\frac{3}{11}\)

B.

\(\frac{2}{9}\)

C.

\(\frac{5}{14}\)

D.

\(\frac{5}{13}\)

Correct answer is C

S = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34}

n(S) = 14

multiples of 3 = {21, 24, 27, 30, 33}

n(multiples of 3) = 5

Prob( picking a multiple of 3) = 5/14

467.

Integrate \(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\).

A.

\(-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x\)

B.

\(2x^2 + \frac{7}{3} x^3 - 5x + 6\)

C.

\(12x^2 + 14x - 5\)

D.

\(-12x^{-4} - 14x + 5\)

Correct answer is A

\(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\)

= \(\frac{4x^{-3 + 1}}{-3 + 1} - \frac{7x^{2 + 1}}{2 + 1} + \frac{5x^{1 + 1}}{1 + 1} - 6x\)

= \(-2x^{-2} - \frac{7}{3} x^3 + \frac{5}{2} x^2 - 6x\)

468.

This table below gives the scores of a group of students in a Further Mathematics Test.

Score 1 2 3 4 5 6 7
Frequency 4 6 8 4 10 6 2

Calculate the mean deviation for the distribution

A.

4.32

B.

2.81

C.

1.51

D.

3.90

Correct answer is C

Score(x) 1 2 3 4 5 6 7 Total Frequency (f) 4 6 8 4 10 6 2 40 fx 4 12 24 16 50 36 14 156 x - \(\bar{x}\) -2.9 -1.9 -0.9 0.1 1.1 2.1 3.1   |x - \(\bar{x}\)| 2.9 1.9 0.9 0.1 1.1 2.1 3.1   f|x - \(\bar{x}\)| 11.6 11.4 7.2 0.4 11 12.6 6.2 60.4

Mean = \(\frac{\sum fx}{\sum f}\)

= \(\frac{156}{40}\)

= 3.9

M.D = \(\frac{\sum f|x - \bar{x}|}{\sum f}\)

= \(\frac{60.4}{40}\)

= 1.51

470.

If M varies directly as N and inversely as the root of P. Given that M = 3, N = 5 and P = 25. Find the value of P when M = 2 and N = 6.

A.

36

B.

63

C.

47

D.

81

Correct answer is D

\(M \propto N \) ; \(M \propto \frac{1}{\sqrt{P}}\).

\(\therefore M \propto \frac{N}{\sqrt{P}}\)

\(M = \frac{k N}{\sqrt{P}}\)

when M = 3, N = 5 and P = 25;

\(3 = \frac{5k}{\sqrt{25}}\)

\(k = 3\)

\(M = \frac{3N}{\sqrt{P}}\)

when M = 2 and N = 6,

\(2 = \frac{3(6)}{\sqrt{P}} \implies \sqrt{P} = \frac{18}{2}\)

\(\sqrt{P} = 9 \implies P = 9^2\)

P = 81