Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

276.

A car travels from calabar to Enugu, a distance of P km with an average speed of U km per hour and continues to benin, a distance of Q km, with an average speed of Wkm per hour. Find its average speed from Calabar to Benin

A.

\(\frac{(p + q)}{pw + qu}\)

B.

\(\frac{uw(p + q)}{pw + qu}\)

C.

\(\frac{uw(p + q)}{pw}\)

D.

\(\frac{uw}{pw + qu}\)

Correct answer is B

Average speed = \(\frac{total Distance}{Total Time}\)

from Calabar to Enugu in time t1, hence

t1 = \(\frac{P}{U}\)

Also from Enugu to Benin

t2 \(\frac{q}{w}\)

Av. speed = \(\frac{p + q}{t_1 + t_2}\)

= \(\frac{p + q}{p/u + q/w}\)

= p + q x \(\frac{uw}{pw + qu}\)

= \(\frac{uw(p + q)}{pw + qu}\)

277.

Simplify 2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9

A.

1 - 4 log3

B.

-1 + 2 log 3

C.

-1 + 5 log2

D.

1 - 2log 2

Correct answer is D

2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9

[\(\frac{2}{5}\))2 x 9] = log \(\frac{4}{25}\) x \(\frac{9}{1}\) x \(\frac{125}{72}\)

= log \(\frac{72}{125}\)

= log \(\frac{5}{2}\)

= log \(\frac{10}{4}\)

= log 10 - log 4

= log10  - log2\(^2\)

= 1 - 2 log2

278.

Musa borrows N10.00 at 2% per month simple interest and repays N8.00 after 4 months. How much does he still owe?

A.

N10.80

B.

N10.67

C.

N2.80

D.

N2.67

Correct answer is C

I = \(\frac{PRT}{100}\)

= \(\frac{10 \times 2 \times 4}{100}\)

= \(\frac{4}{5}\)

= 0.8

Total amount = N10.80

He pays N8.00

Remainder = 10.80 - 8.00

= N2.80

279.

Find the probability that a number selected at random from 41 to 56 is a multiple of 9

A.

\(\frac{1}{8}\)

B.

\(\frac{2}{15}\)

C.

\(\frac{3}{16}\)

D.

\(\frac{7}{8}\)

Correct answer is A

Given from 41 to 56

41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56

The nos multiple of 9 are: 45, 54

P(multiple of 9) = \(\frac{2}{16}\)

= \(\frac{1}{8}\)

280.

Two numbers are removed at random from the numbers 1, 2, 3 and 4. What is the probability that the sum of the numbers removed is even?

A.

\(\frac{2}{3}\)

B.

\(\frac{1}{2}\)

C.

\(\frac{1}{3}\)

D.

\(\frac{1}{4}\)

Correct answer is B

\(\begin{array}{c|c} 1 & 2 & 3 & 4\\\hline 1(1, 1) & (1, 2) & (1, 3) & (1, 4)\\ \hline 2(2, 1) & (2 , 2) & (2, 3) & (2, 4) \\ \hline 3(3, 1) & (3, 2) & (3, 3) & (3, 4)\\ \hline 4(4, 1) & (4, 2) & (4, 3) & (4, 4)\end{array}\)

sample space = 16

sum of nos. removed are (2), 3, (4), 5

3, (4), 5, (6)

(4), 5, (6), 7

(5), 6, 7, (8)

Even nos. = 8 of them

Pr(even sum) = \(\frac{8}{16}\)

= \(\frac{1}{2}\)