How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
25
21
16
3
Correct answer is B
Number of people playing both rugby and cricket = 4 Number that play cricket only = 11 - 4 = 7 Number that play rugby only = 14 - 4 = 10. Number that play for at least one of the teams = 4 + 7 + 10 = 21.
Simplify \(\frac{\sqrt{12} - \sqrt{3}}{\sqrt{12} + \sqrt{3}}\)
\(\frac{1}{3}\)
9
16cm
3
Correct answer is A
\(\frac{\sqrt{12} - \sqrt{3}}{\sqrt{12} + \sqrt{3}}\)
\(\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}\)
\(\therefore \frac{\sqrt{12} - \sqrt{3}}{\sqrt{12} + \sqrt{3}} = \frac{2\sqrt{3} - \sqrt{3}}{2\sqrt{3} + \sqrt{3}}\)
= \(\frac{\sqrt{3}}{3\sqrt{3}}\)
= \(\frac{1}{3}\)
Evaluate \(\frac{(81)^{\frac{3}{4}} - (27)^{\frac{1}{3}}}{3 \times 2^3}\)
27
1
\(\frac{1}{3}\)
\(\frac{1}{8}\)
Correct answer is B
\(\frac{(81)^{\frac{3}{4}} - (27)^{\frac{1}{3}}}{3 \times 2^3}\)
= \(\frac{(3^{4})^{\frac{3}{4}} - (3^{3})^{\frac{1}{3}}}{3 \times 2^{3}}\)
= \(\frac{3^{3} - 3^{1}}{24}\)
= \(\frac{27 - 3}{24} = 1\)
Express the product of 0.0014 and 0.011 in standard form
1.54 x 10-2
1.54 x 10-3
1.54 x 10-4
1.54 x 10-5
Correct answer is D
\(0.0014 = 1.4 \times 10^{-3}\)
\(0.011 = 1.1 \times 10^{-2}\)
\(\therefore 0.0014 \times 0.011 = 1.4 \times 10^{-3} \times 1.1 \times 10^{-2}\)
= \(1.54 \times 10^{-5}\)
N28,800
N29,040
N31,200
N31,944
Correct answer is B
Present salary = N24,000.
Increment after first year = \(\frac{10}{100} \times N24,000 = N2,400\)
Salary at the beginning of second year = N(24,000 + 2,400)
= N26,400.
Increment after second year = \(\frac{10}{100} \times N26,400 = N2,640\)
Salary at the beginning of third year = N(26,400 + 2,640)
= N29,040.
\(\therefore\) His salary at the beginning of the third year = N29,040.