Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,366.

\(\begin{array}{c|c} Class & Frequency\\ \hline 1 - 5 & 2\\6 - 10 & 4\\11 - 15 & 5\\16 - 20 & 2 \\ 21 - 25 & 3\\26 - 30 & 2\\31 - 35 & 1\\36 - 40 & 1 \end{array}\)
Find the median of the observation in the table given

A.

11.5

B.

12.5

C.

14.0

D.

14.5

Correct answer is D

Median = L1 + (\(\frac{Ef}{fm}\)) - fo

\(\frac{\sum f}{2}\)

= \(\frac{20}{2}\)

= 10, L1 = 10.5, fo = 6, fm = 5

Median = 10.5 + \(\frac{(10 - 6)}{5}\)5

= 10.5 + 4

= 14.5

2,367.

The mean of the ages of ten secondary school pupils is 16 but when the age of their teacher is added to it the men becomes 19. Find the age of the teacher

A.

27

B.

35

C.

38

D.

49

Correct answer is D

Average age of 110 students = 16

∴ Total age = 16 x 10 = 160 years

Age of teachers = x, total number of people now = 11

mean age = 19

Total age of new group = 19 x 11 = 209

Age of teachers = x = (209 - 160) = 49 yrs

2,368.

\(\begin{array}{c|c} Weight(s) & 0 -10 & 10 - 20 & 20 - 30 & 40 - 50\\ \hline \text{Number of coconuts} & 10 & 27 & 19 & 6 & 2\end{array}\)
Estimate the mode of the frequency distribution above

A.

13.2g

B.

15.0g

C.

16.8g

D.

17.5g

Correct answer is C

Mode = a + \(\frac{(b - a)(F_m - F_b)}{2F_m - F_a - F_b}\)

= \(L_1 + \frac{\Delta_1 x^\text{c}}{\Delta_1 + \Delta_2}\)

= \(10 + \frac{(20 - 10)(27 - 10)}{2(27) - 10 - 19}\)

= 10 + \(\frac{170}{25}\)

= 10 + 6.8

= 16.8

2,369.

The following marks were obtained by twenty students in an examination: 53, 30, 70, 84, 59, 43, 90, 20, 78, 48, 44, 60, 81, 73, 50, 37, 67, 68, 64, 52. Find the numbers of students who scored at least 50 marks

A.

6

B.

10

C.

13

D.

14

Correct answer is D

Number of students scoring at least 50 marks = Number of students scoring 50 and above From the table 53, 70, 84, 59, 90, 60, 81, 73, 50, 37, 67, 68, 64, 52. Hence, 14 students scored at least 50 marks

2,370.

Quantities in the proportions 1, 4, 6, 7 are to be represented in a pie chart. Calculate the angle of the sector with proportion 7

A.

20o

B.

80o

C.

120o

D.

140o

Correct answer is D

Angle corresponding to 7 in a pie chart will be \(\frac{7 \times 360}{\text{sum of items}}\)

= \(\frac{7 }{18}\) x 360

= 140o