How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the median of the numbers 89, 141, 130, 161, 120, 131, 131, 100, 108 and 119
131
125
123
120
Correct answer is B
50o
65o
74o
88o
Correct answer is C
Anambra = \(\frac{185}{900}\) x \(\frac{360}{1}\)
= 74o
N96.00
N112.00
N136.00
N160.00
Correct answer is B
Total surface area(s) = 2(4 x 3) + 2(4 x 4)
= 2(12) + 2(16)
= 24 + 32
= 56cm2
1m2 costs N2.00
∴ 56m∴ will cost 56 x N2.00
= N112.00
The perpendicular bisector of UV
A circle with UV as radius
A line parallel to the line UV
A circle with the line UV as the diameter
Correct answer is D
No explanation has been provided for this answer.
Find the total surface area of solid cone of radius 2\(\sqrt{3}\)cm and slanting side 4\(\sqrt{3}\)
8\(\sqrt{3}\pi \)cm2
24\(\pi \)cm2
15\(\sqrt{3}\pi \)cm2
36\(\pi \)cm2
Correct answer is D
Total surface area of a solid cone
r = 2\(\sqrt{3}\)
= \(\pi r^2\) + \(\pi\)rH
H = 4\(\sqrt{3}\), \(\pi\)r(r + H)
∴ Area = \(\pi\)2\(\sqrt{3}\) [2\(\sqrt{3}\) + 4\(\sqrt{3}\)]
= \(\pi\)2\(\sqrt{3}\)(6\(\sqrt{3}\))
= 12\(\pi\) x 3
= 36\(\pi \)cm2