How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\sqrt{2}\)
\(\frac{1}{2}\)
22
1
2 - 1
Correct answer is A
45o = \(\frac{x}{2}\), Since 45o = \(\frac{1}{\sqrt{2}}\)
x = 2 x \(\frac{1}{\sqrt{2}}\)
= \(\frac{2\sqrt{2}}{2}\)
= \(\sqrt{2}\)
(1.75, 5)
(1.75, 2)
(1.75, 1)
(65, 74)
Correct answer is B
\(\begin{array}{c|c}x & f & fx\\ \hline 0 & 3 & 0\\ 1 & 5 & 5\\ 2 & 7 & 14\\ 3 & 4 & 12\\4 & 1 & 4\\5 & 0 & 0\end{array}\)
\(\sum{f}\) = 20
\(\sum fx\) = 35
Mean = \(\frac{\sum fx}{\sum f}\)
= \(\frac{35}{20}\)
= \(\frac{7}{4}\)
= 1.75
Mode = 2
= 1.75, 2
-32
-14
40
22
37
Correct answer is C
When x = -3, y = 4 - 3(3) - (-3)3
= 4 + 9 + 27
= 13 + 27
= 40
In \(\bigtriangleup\) XYZ, XY = 13cm, YZ = 9cm, XZ = 11cm and XYZ = \(\theta\). Find cos\(\theta\)o
\(\frac{4}{39}\)
\(\frac{43}{39}\)
\(\frac{209}{3}\)
\(\frac{43}{78}\)
Correct answer is D
cos\(\theta\) = \(\frac{13^2 + 9^2 - 11^2}{2(13)(9)}\)
= \(\frac{169 + 81 - 21}{26 \times 9}\)
cos\(\theta\) = \(\frac{129}{26 \times 9}\)
= \(\frac{43}{78}\)
If f(x - 2) = 4x2 + x + 7, find f(1)
12
27
7
46
17
Correct answer is D
f(x - 2) = 4x2 + x + 7
x - 2 = 1, x = 3
f(x - 2) = f(1)
= 4(3)2 + 3 + 7
= 36 + 10
= 46