How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the mean of the following 24.57, 25.63, 24.32, 26.01, 25.77
25.12
25.30
25.26
25.50
25.75
Correct answer is C
\(\frac{24.57 + 25.63 + 24.32 + 26.01 + 25.77}{5}\)
mean = \(\frac{126.3}{5}\)
= 25.26
P = 60o and R = 90o
P = 30o and R = 120o
P = 90o and R = 60o
P = 60o and R 60o
P = 45o and R = 105o
Correct answer is A
By using cosine formula, p2 = Q2 + R2 - 2QR cos p
Cos P = \(\frac{Q^2 + R^2 - p^2}{2 QR}\)
= \(\frac{(3)^2 + 2(\sqrt{3})^2 - 3^2}{2\sqrt{3}}\)
= \(\frac{3 + 12 - 9}{12}\)
= \(\frac{6}{12}\)
= \(\frac{1}{2}\)
= 0.5
Cos P = 0.5
p = cos-1 0.5 = 60°
= < P = 60°
If < P = 60° and < Q = 30
< R = 180° - 90°
angle P = 60° and angle R is 90°
25cm
18cm
36cm
29cm
25.5cm
Correct answer is A
Circumference of PRS = \(\frac{\pi}{2}\) = \(\frac{22}{7}\) x \(\frac{7}{1}\) x \(\frac{1}{2}\)
= 11cm
Side PT = 7cm, Side TR = 7cm
Perimeter(PTRS) = 11cm + 7cm + 7cm
= 25cm
Simplify \(\sqrt[3]{\frac{27a^{-9}}{8}}\).
\(\frac{9a^2}{2a^3}\)
\(\frac{3}{2a^3}\)
\(\frac{2}{3a^2}\)
\(\frac{3a^2}{2}\)
Correct answer is B
\(\sqrt[3]{\frac{27a ^{-9}}{8}}\) = \(\frac{3a^{-3}}{2}\)
= \(\frac{3}{2}\) x \(\frac{1}{a^3}\)
= \(\frac{3}{2a^3}\)
6.00cm2
6.10cm2
6cmv
6.09cm2
4.00cm2
Correct answer is B
Area of the paper = area of square = L x B or S2
where s = S x k
Area of the paper = (2.524)2
area of the diagram = (0.524)2
area not covered = (2.524)2 - (0.524)2
= 6.370576 - 0.274576
= 6.096
= 6.10cm2 (2 s.f)