How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the solution of the equation x + 2\(\sqrt{x} - 8\) = 0
(4, 16)
(2, 4)
(4, 1)
(1, 16)
(16, 16)
Correct answer is A
x + 2\(\sqrt{x} - 8 = 0, Let \sqrt{x} = y\)
x = \(y^2\)
\(y^2 + 2y\) - 8 = 0
(y + 4)(x - 2) = 0
y = -4 or 2
x = 16 or 4
What will be the value of k so that the quadratic equation kx2 - 4x + 1 = 0 has two equal roots?
2
3
4
8
\(\frac{1}{4}\)
Correct answer is C
kx2 - 4x + 1 = 0, comparing with ax2 + bx + c = 0
a = k, b = -4, c = 1 for equal root b2 = 4ac
(-4)2 = 4k
k = \(\frac{16}{4}\)
= 4
(\(\frac{x^a}{x^b}\))a + b = (\(\frac{x^{a + b}}{x^{a - b}}\))\(\frac{a^2}{b}\)
x-a2
xb2
xa2 - b2
\(\frac{1}{x^{a2 + b2}}\)
xb2 - a2
Correct answer is D
(\(\frac{x^a}{x^b}\))a + b = (\(\frac{x^{a2 + ab}}{x^{b2 + ab}}\))
= xa2 - b2
{\(\frac{xa + b}{xa - b}\)} = xa + b - a + b
= x2b
= x2a
= xa2 - b2
= xb2 \(\div \) a2 = \(\frac{1}{x^\text a2 + b2}\)
Find the product of (2\(\sqrt{y - 3y}\)) and (3y = 2y)
4y = y2
4y + 9y2
4y - 9y2
-4y - 9y2
2y + y2
Correct answer is C
(2\(\sqrt{y - 3y}\))(3y = 2y)
= 6y y + 4y - 9y2 - 6y\(\sqrt{y}\)
= 4y - 9y2
60o
108o
120o
150o
None of the above
Correct answer is C
The sum of interior angle of pentagon
(5 sides) = (2n - 4) x 90o
n = 5
(2 x 5 - 4) x 90o = 6 x 90o
= 540o
540o - 60o = 480o \(\div\) 4
= 120o