Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,156.

If log 5.957 = 0.7750, find log \(3 \sqrt{0.0005957}\)

A.

4.1986

B.

2.9250

C.

1.5917

D.

1.2853

Correct answer is B

\(3 \sqrt{0.0005957}\)

\(\begin{array}{c|c} \log No(0.0005957) & \frac{1}{3} \log \frac{1}{3} \\ \hline (0.0005957)^{\frac{1}{3}} & 4.7750 \times \frac{1}{3} \\ & 6 + 2.7750 \\\hline & 3 \\\hline & 2.9250\end{array}\)

1,157.

If a number is selected at random from each of the sets p = {1, 2, 3} and Q = {2, 3, 5}, find the probability that the sum of the numbers is prime

A.

\(\frac{5}{9}\)

B.

1\(\frac{4}{9}\)

C.

\(\frac{1}{3}\)

D.

\(\frac{2}{9}\)

Correct answer is C

p = { 1, 2, 3}

Q = {2, 3, 5}

prob(prime number) = prob(1 and 2) or

= prob(2 and 3) or

= prob(3 and 2)

There are three possibilities of the sum being prime

Total possibility = 9

probability(sum being prime) = \(\frac{3}{9}\)

= \(\frac{1}{3}\)

1,159.

In parallelogram PQRS, QR is produced to M such that |QR| = |RM|. What fraction of the area of PQMS is the area of PRMS?

A.

\(\frac{1}{4}\)

B.

\(\frac{1}{3}\)

C.

\(\frac{2}{3}\)

D.

\(\frac{3}{4}\)

Correct answer is C

There are 3 triangles: \(\bigtriangleup\)MRS, \(\bigtriangleup\) and \(\bigtriangleup\) PRQ

Area PRMS has 2 triangles: \(\bigtriangleup\) MRS and \(\bigtriangleup\) RSP

the fraction = \(\frac{2}{3}\)

1,160.

A chord subtends an angle of 120o at the centre of a circle of radius 3.5cm. Find the perimeter of the minor sector containing the chord, [Take \(\pi = \frac{22}{7}\)]

A.

14\(\frac{1}{3}\)cm

B.

12\(\frac{5}{6}\)cm

C.

8\(\frac{1}{7}\)cm

D.

7\(\frac{1}{3}\)cm

Correct answer is A

perimeter of minor sector

2r + \(\frac{\theta}{360} \times 2 \pi r\)

= 2 x 3.5 + \(\frac{120^o}{360^o} \times 2 \frac{22}{7} \times 3.5\)

= 7 + \(\frac{154}{21}\)

= 7 + 7.33

= 14.33

= 14\(\frac{1}{3}\)cm