Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

796.

What sum of money will amount to D10,400 in 5 years at 6% simple interest?

A.

D8,000.00

B.

D10,000.00

C.

D12,000.00

D.

D16,000.00

Correct answer is A

A = P + 1

I = A - P

= 10,400 - P

Now using I = \(\frac{P \times T \times R}{100}\)

i.e. 10,400 - P = \(\frac{P \times 5 \times 6}{100}\)

= 100(10,400 - P) = 30P

10(10,400 - P) = 3P

104,000 - 10P = 3P

104,000 - 10P = 3P

104,000 = 3P + 10P

= 104,000 = 13P

P = \(\frac{104,000}{100}\)

P = D8,000

797.

Simplify; \(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)

A.

32n

B.

9

C.

3n

D.

3n + 1

Correct answer is B

\(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)

= \(\frac{3^{n - 1} \times 3^{3(n + 1)}}{3^{4n}}\)

= 3\(^{n - 1 + 3n + 3 - 4n}\)

= 3\(^{4n - 4n - 1 + 3}\)

= 32

= 9

798.

On a map, 1cm represent 5km. Find the area on the map that represents 100km2.

A.

2cm2

B.

4cm2

C.

8cm2

D.

8cm2

Correct answer is B

On a map, 1cm represents 5km. Then it follows that 1cm2 represents 25km2. Acm2 represents 100km2. By apparent cross-multiplication, 1cm2 x 100km2 = Acm2x 25km2

therefore A = \(\frac{100}{25}\) = 4cm2

799.

Which of following is a valid conclusion from the premise. "Nigeria footballers are good footballers"?

A.

Joseph plays football in Nigeria therefore he is a good footballer

B.

Joseph is a good footballer therefore he is a Nigerian footballer

C.

Joseph is a Nigerian footballer therefore he is a good footballer

D.

Joseph plays good football therefore he is a Nigerian footballer

Correct answer is C

From the venn diagram, Nigeria footballers from a subset of good footballers.

800.

The distance, d, through which a stone falls from rest varies directly as the square of the time, t, taken. If the stone falls 45cm in 3 seconds, how far will it fall in 6 seconds?

A.

90cm

B.

135cm

C.

180cm

D.

225cm

Correct answer is C

d \(\alpha\) t2

d = t2 k

where k is a constant. d = 45cm, when t = 3s; thus 45 = 32 x t

k = \(\frac{45}{9}\) = 5

thus equation connecting d and t is d = 5t2

when t = 6s, d = 5 x 62

= 5 x 36

= 180cm