How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Approximate 0.9875 to 1 decimal place.
1.1
1.0
0.9
0.10
Correct answer is B
9 is on one decimal place, the next number to it is 8 which will be rounded up to 1 because it is greater than 5 and then added to 9 to give 10, 10 cannot be written, it will then be rounded up to 1 and added to 0. So the answer is 1.0
Calculate the area of an equilateral triangle of side 8cm
8√3
16
4√3
16√3
Correct answer is D
An equilateral triangle has all sides equal and all angles equal as 600
Area = \(\frac{1}{2}\) absinθ
Area = \(\frac{1}{2}\) x 8 x 8 x sin60
= \(\frac{1}{2}\) x 64 x \(\sqrt{\frac{3}{2}}\)
= 16√3 cm\(^2\)
Which one of the following gives the members of the set A1 n B n C?
Φ
{s}
{t, u}
{y, z}
Correct answer is A
A1 = Elements in the universal set but not in A = {s, w, x, y, z} B = {r, s. t, u} C = {t, u, v, w, x} A1 n B n C = elements common to the three sets = none = empty set = Φ
\(\frac{2}{3}\)
\(\frac{1}{3}\)
\(\frac{1}{4}\)
\(\frac{1}{9}\)
Correct answer is D
Total number of balls = 2 + 4 = 6
P(of picking a red ball) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
P(of picking a blue ball) = \(\frac{4}{6}\) = \(\frac{2}{3}\)
With replacement,
P( picking two red balls) = \(\frac{1}{3}\) × \(\frac{1}{3}\) = \(\frac{1}{9}\)
if y = 23\(_{five}\) + 101\(_{three}\) find y leaving your answer in base two
1110
10111
11101
111100
Correct answer is B
First we convert the numbers to base ten
23\(_{five}\)= 2 x 51 + 3 x 50
= 10 + 3 = 13
101\(_{five}\) = (1 x 32) + (0 x 31) + (1 x 30)
= 9 + 0 + 1 = 10
So, y = 13 + 10 = 23
To convert 23 to base 2 (as in the diagram above)
Y = 23
= 10111\(_{five}\)
Answer is B