How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\sqrt{3 - 2}\)
2 - \(\sqrt{3}\)
\(\sqrt{3}\)
-2
Correct answer is C
Tan 60 = 3; Tan 30 = 1
\(\frac{\tan 60^o - 1}{1 - tan 30^o}\) = \(\frac{\sqrt{3 - 1}}{1 - \frac{1}{\sqrt{3}}}\) = \(\frac{\sqrt{3 - 1}}{\frac{3 - 1}{\sqrt{3}}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3 - 1}}{\sqrt{3}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3}}{\sqrt{3}}\)
= \(\sqrt{3}\)
A bearing of 320\(^o\) expressed as a compass bearing is
N 50\(^o\) W
N 40\(^o\) W
N 50\(^o\) E
N 40\(^o\) E
Correct answer is B
No explanation has been provided for this answer.
If P(2,3) and Q)2, 5) are points on a graph, calculate the length PQ
6 units
5 units
4 units
2 units
Correct answer is D
\(\sqrt{(x_2 - x_1)^2 + (y_2 - Y_1)^2}\)
= \(\sqrt{(2 - 2)^2 + (5 - 3)^2}\)
= \(\sqrt{0^2 + 2^2}\)
= \(\sqrt{4}\)
= 2 units
Calculate the gradient (slope) of the joining points (-1, 1) and (2, -2)
-1
\(\frac{-1}{2}\)
\(\frac{1}{2}\)
1
Correct answer is A
Gradient = m = \(\frac{y_2 - y_1}{x_2 - x_1}\)
= \(\frac{-2 -1}{2 + 1}\)
= \(\frac{-3}{3}\)
= -1
Which of the following is true about parallelogram?
opposite angles are supplementary
opposite angles are complementary
opposite angles are equal
opposite angles are reflex angles
Correct answer is C
No explanation has been provided for this answer.