Data Interpretation questions and answers

Data Interpretation Questions and Answers

Data Interpretation questions test one's ability in analysing data, inspecting the elements in data and interpreting them to extract maximum information from the given set of data or information. The data is usually given in the form of charts, tables and graphs.

Practise with our Data Interpretation questions and answers to help you know what to expect, improve your speed and confidence and be really prepared for the actual test.

86.

The following line graph gives the percent profit earned by two Companies X and Y during the period 1996 - 2001.

Percentage profit earned by Two Companies X and Y over the Given Years

%Profit = ((Income - Expenditure) / Expenditure) x 100

If the expenditure of Company Y in 1997 was Rs. 220 crores, what was its income in 1997 ?

A.

Rs. 312 crores

B.

Rs. 297 crores

C.

Rs. 283 crores

D.

Rs. 275 crores

Correct answer is B

Profit percent of Company Y in 1997 = 35.

Let the income of Company Y in 1997 be Rs. x crores.

Then, 35 = (x - 220)/220 x 100  =>  x = 297

Therefore Income of Company Y in 1997 = Rs. 297 crores.

87.

The following line graph gives the percent profit earned by two Companies X and Y during the period 1996 - 2001.

Percentage profit earned by Two Companies X and Y over the Given Years

%Profit = ((Income - Expenditure) / Expenditure) x 100

The incomes of two Companies X and Y in 2000 were in the ratio of 3:4 respectively. What was the respective ratio of their expenditures in 2000 ?

A.

7:22

B.

14:19

C.

15:22

D.

27:35

Correct answer is C

Let the incomes in 2000 of Companies X and Y be 3x and 4x respectively.

And let the expenditures in 2000 of Companies X and Y be E1 and E2 respectively.

Then, for Company X we have:

65 = (3x - E1)/E1 x 100  =>  65/100 = 3x/E1 - 1  =>  E1 = 3x x ( 100/165 ) .... (i)

For Company Y we have:

50 = (4x - E2)/E2 x 100  =>  50/100 = 4x/E2 - 1 => E2 = 4x x ( 100/150 ) .... (ii)

From (i) and (ii), we get:

E1/E2 = (3x x ( 100/165 ))/(4x x ( 100/150 )) = (3 x 150)/(4 x 165) = 15/22 (Required ratio)

88.

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies over the Years (Number in Thousands)

The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year ?

A.

173%

B.

164%

C.

132%

D.

97%

Correct answer is B

Required percentage = ( 128000/78000 x 100 ) %

≈ 164%

89.

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies over the Years (Number in Thousands)

In which of the following years, was the difference between the productions of Companies X and Y the maximum among the given years ?

A.

1997

B.

1998

C.

1999

D.

2000

Correct answer is D

The difference between the productions of Companies X and Y in various years are:

For 1997 (139000 - 119000) = 20000.

For 1998 (120000 - 99000) = 21000.

For 1999 (141000 - 100000) = 41000.

For 2000 (128000 - 78000) = 50000.

For 2001 (120000 - 107000) = 13000.

For 2002 (159000 - 148000) = 11000.

Clearly, maximum difference was in 2000

90.

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies over the Years (Number in Thousands)

What is the average numbers of vehicles manufactured by Company X over the given period ? (rounded off to nearest integer)

A.

119333

B.

113666

C.

112778

D.

111223

Correct answer is A

Average number of vehicles manufactured by Company X

= 1/6 x (119000 + 99000 + 141000 + 78000 + 120000 + 159000)

= 119333.