If the mean of 3, 5, 8, k, 14 and 17 is 11, what is the value of k
58
38
19
11
967
Correct answer is C
To calculate Mean: add up all the numbers ⇒ 3+5+8+k+14+17 = 47 + k then divide by how many numbers there are ⇒ 6 The Mean is already given as 11 11 = (47 + k) / 6 Cross multiply to solve for k : k = (6 X 11) - 47 k = 19
The bearing of a point Y from point x is 150°. What is the bearing of X from Y?
330°
240°
150°
120°
30°
Correct answer is A
No explanation has been provided for this answer.
Simplify 27\(^{-\frac{1}{3}}\) \(\times\) 64\(^{-\frac{1}{3}}\) \(\times\) 4\(^{\frac{1}{3}}\)
48
12
\(\frac{4}{3}\)
\(\frac{1}{12}\)
\(\frac{1}{48}\)
Correct answer is D
No explanation has been provided for this answer.
Find the 19th term of the A.P. \(\frac{5}{6}\), \(\frac{8}{6}\), \(\frac{11}{6}\).................
7\(\frac{1}{2}\)
9
9\(\frac{1}{2}\)
9\(\frac{5}{6}\)
10
Correct answer is D
first term (a) = \(\frac{5}{6}\)
common difference = \(\frac{8}{6}\) - \(\frac{5}{6}\) → \(\frac{3}{6}\) or \(\frac{1}{2}\)
A.P formula → T\(_n\) = a + (n - 1)d
T\(_n\) = \(\frac{5}{6}\) + (19 - 1)\(\frac{1}{2}\)
T\(_n\) = \(\frac{5}{6}\) + 9
→ 9\(\frac{5}{6}\)
11.60%
7.60%
15%
17.65%
Correct answer is C
Using these:
Loss = C.p - S.p
: Percentage Loss = ( Loss X 100) ÷ C.p
=15 %