The work done in extending a spring by 40 mm is 1.52J. Calculate the elastic constant of the spring.
38.8 Nm-1
60.8 Nm-1
190.0 Nm-1
1900.0 Nm-1
3800.0 Nm-1
Correct answer is D
Force = Elastic constant x extension
Work done = 12K×e2
Given Work done = 1.52J; Elastic constant (k) = ?; e = 40mm = 0.04 m
∴
3.04 = k \times 1.6 \times 10^{-3}
k = \frac{3.04}{1.6} \times 10^3
= 1.9 x 10^3
= 1900 Nm^{-1}
In the electrical method of making a magnet, the polar the magnet formed depends on the
amount of current passed
direction of the current
nature of the material used
orientation of the magnetic material in space
size of the magnetic material
Correct answer is B
No explanation has been provided for this answer.
zero
2.5
10
12.5
100
Correct answer is A
No explanation has been provided for this answer.