The density of a body is 5×103kgm−3 and it w...
The density of a body is 5×103kgm−3 and it weighs 1N in air. Calculate the apparent weight of the body when totally immersed in water. (Density of water =103kgm−3,g=10ms−2 )
0.02N
0.08N
0.20N
0.80N
1N
Correct answer is D
Upthrust = weight of the water displaced =pvg= 1000 x 2 x 10−5=0.20N \\ Apparent weight = weight in air – upthrust = 1-0.2N=0.8N
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