\(2.5\times10^{-7}\)m
\(3.8\times10^{-7}\)m
\(4.6\times10^{-7}\)m
\(5.2\times10^{-7}\)m
\(6.1\times10^{-7}\)m
Correct answer is B
n =\(\frac{wavelength\, in\, air}{wavelength\, in \,medium}= \frac{5.9\times10^{-7}}{1.54}= 3.8\times10^{-7}\)m
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