1.2 x \(10^{-5}K{-1}\)
2.5x \(10^{-5}K{-1}\)
3.5x \(10^{-5}K{-1}\)
4.5x \(10^{-5}K{-1}\)
5x \(10^{-5}K{-1}\)
Correct answer is E
\(\alpha = \frac{I_2-I_1}{I_1(\theta_2-\theta_1)} \\ \Rightarrow \frac{40.05 - 40}{40 \times (45-20)} = 5.0 \times10^{-5}\)