The angle of elevation of the top of a tower from a point...
The angle of elevation of the top of a tower from a point on the horizontal ground, 40m away from the foot of the tower is 30o. Find the height of the tower.
20m
40√3m/3
20√3m
40√3m
60cm
Correct answer is B
\(\tan 30 = \frac{x}{40}\)
\(x = 40 \tan 30 = \frac{40}{\sqrt{3}}\)
= \(\frac{40\sqrt{3}}{3} m\)
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