In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
A.
36o
B.
72o
C.
108o
D.
144o
E.
288o
Correct answer is B
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°