In the diagram above, O is the center of the circle PQRS ...
In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
A.
36o
B.
72o
C.
108o
D.
144o
E.
288o
Correct answer is B
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°
Similar Questions
Express \(\frac{1}{x^{3}-1}\) in partial fractions ...
The area of a circle of radius 4cm is equal to (Take π = 3.142 ) ...
Find the value of sin 45° - cos 30° ...
The solution of the quadratic equation px2 + qx + b = 0 is...
Which of the following equations has its roots as 4 and -5?...