A man and his wife are both heterozyous for the sickle-cell trait. The likely percentage of their offspring being either carriers or sicklers is
75%
50%
25%
100%
Correct answer is A
A heterozygote for sickle-cell anaemia = AS
Crossing two AS persons, we have one AA, two AS, and one SS.
∴ The probability that the children are either carriers or sicklers = ¾
= 75%