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A shooter wants to fire a bullet in such a way that its h...

A shooter wants to fire a bullet in such a way that its horizontal range is equal to three times its maximum height. At the what angle should he fire the bullet to achieve this?

A.

68o

B.

53o

C.

30o

D.

45o

Correct answer is B

Horizontal range = 3 x maxi. height
=> (U2Sin2θ) / g = (3 x U2sin2θ) / 2g

∴sin2θ = 3sin2θ
2

=> 2sinθcosθ = 3sin2θ
2

∴ 4sinθcosθ = 3sin2θ
=> 4cosθ = 3sinθ
sinθ/cosθ = 4/3; => tanθ = 4/3 = 1.3333
θ = tan-1 (1.3333)
= 53o