Find ∫(sin x + 2)dx
...Find ∫(sin x + 2)dx
cos x + x2 + K
cos x 2x + K
-cos x + x2 + K
-cos x + 2x + K
Correct answer is D
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
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