Evaluate \(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x d...
Evaluate ∫π2−π2cosxdx
zero
1
2
3
Correct answer is C
∫π2−π2cosxdx=[sinx]π2−π2=sinπ2−sin−π2
= sin90 – sin-90
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2
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